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The parseDate operator extracts a date or time from a string and provides a timestamp in milliseconds. 


To convert an epoch timestamp to a human-readable format, use the formatDate operator.


  • parseDate(<strDate>, <dateFormat>)
  • parseDate(<strDate>, <dateFormat>, <timeZone>)


  • strDate must start with the characters to match with the dateFormat pattern. For example, "3/4/2005 other" but not "other 3/4/2005".
  • dateFormat is a pattern string, such as "MM/dd/yyyy HH:mm:ss a". A full list of the supported patterns can be found on Java's simpledateformat documentation.
  • If you do not supply timeZone, the operator defaults to the time zone set in your preferences. For a list of timeZone codes, see the List of tz database time zones.


Given the date 2019-11-18T19:00:00.000-08:00 you'd specify the dateFormat as yyyy-MM-dd'T'HH:mm:ss.SSSXXX. For example,

| parseDate(date, "yyyy-MM-dd'T'HH:mm:ss.SSSXXX") as milliseconds  

Given a log message such as:

instance of Win32_NTLogEvent
EventIdentifier = 100;
Logfile = "Application";
RecordNumber = 894528;
SourceName = "Bonjour Service";
TimeGenerated = "20170720000030.000000-000";
TimeWritten = "20170720000030.000000-000";
Type = "Error";

The following query returns TimeGenerated as a timestamp in milliseconds, in this example 1500534030000.

| parse "TimeGenerated = \"*.000000-000" as dd | parseDate(dd, "yyyyMMddHHmmss") as milliseconds

To specify a time zone:

| parseDate(dd, "yyyyMMddHHmmss", "etc/utc") as milliseconds

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